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7n^2-7=-12n
We move all terms to the left:
7n^2-7-(-12n)=0
We get rid of parentheses
7n^2+12n-7=0
a = 7; b = 12; c = -7;
Δ = b2-4ac
Δ = 122-4·7·(-7)
Δ = 340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{340}=\sqrt{4*85}=\sqrt{4}*\sqrt{85}=2\sqrt{85}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{85}}{2*7}=\frac{-12-2\sqrt{85}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{85}}{2*7}=\frac{-12+2\sqrt{85}}{14} $
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